3x^2+64=(2x^2)/(2)

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Solution for 3x^2+64=(2x^2)/(2) equation: 


x in (-oo:+oo)

3*x^2+64 = (2*x^2)/2 // - (2*x^2)/2

3*x^2-((2*x^2)/2)+64 = 0

3*x^2-x^2+64 = 0

2*x^2 = -64 // : 2

x^2 = -32

x belongs to the empty set

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